The scalar wave energy cannot be measured directly. Instead, we can consider the current passing through the link cable, which is directly converted to scalar wave energy. This is in the order of 70.7 mA. The potential difference between the transmitter and receiver coils is approximately 200v. P = I^2 * R. The power being received by the receiver coil is therefore 1 watt. This energy is directly converted to the scalar field, with a very high conversion efficiency.
What is the scalar wave unit output power in Tesla’s or output power from the amplifier?
16
Apr
Sorry, but I don’t follow your math. 200*.0707 is 14.14 watts. How do you get to 1 watt at receiving coil? Is it loss across the air gap? What is you distance calculation?
What is the value of R?
Maybe I’ve go this calculation wrong but I don’t know.
Thanks,
Terry
Hi Terry. The emissive power was measured using a scalar antennae between the transmitter and receiver.
Hello.
I do not understand this derivation. (I note that I have an education in electrical engineering.) Where did the claim come from: The potential difference between the transmitter and receiver coils is approximately 200v? Where do I measure those 200V? On the link cable? Well it never! And how is the relation “P = I^2 * R” related to this, what does the ohmic resistance R relate to and how big is it?
Thank you for further clarification.
Hi Jaroslav. The voltage potential is measured between opposing phases of the two coils. These two coils are 180 degrees opposed. The ohmic value is derived from the Scalar Digitizer resistance, which has zero phase component.